Question :
A diode circuit is so arranged that when the switch is open it's KVL gives
Ri+ 1/C ∫i dt = 0
When the switch is closed,
Ri+ 1/C ∫i dt = Vs
Vs is the dc supply voltage.
The diode is so connected that it is forward biased when switch is closed
The circuit is mostly likely be a
1. diode in parallel with Vs, switch, R & C
2. diode in series with R, than parallel with Vs & C
3. diode in series with the switch, R, C & Vs
4. diode in series with R,C & Vs with the switch connected in parallel across Vs
Answer :
3 - diode in series with the switch, R, C & Vs
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